Capacitance to Charge Calculator
Calculate electric charge from capacitance and voltage with Q = C × V, in pF, nF, μF, mF or F. Also shows stored energy, E = ½CV².
uF
V
ELECTRIC CHARGE
0.0012 C
COULOMBS
1.200e-3 C
FORMULA
Q = C × V
ENERGY (J)
0.0072 J
💡 How to Calculate Charge from Capacitance
To find the charge on a capacitor, multiply its capacitance in farads by the voltage across it: Q = C × V. Convert the capacitance to farads first (1 μF = 10−6 F). The charge comes out in coulombs.
Charge and energy formulas
Q = C × V · E = ½ × C × V² = ½ × Q × V
Q = charge in coulombs, C = capacitance in farads, V = voltage in volts, E = stored energy in joules
Example: 100 μF at 12 V → Q = 100 × 10−6 × 12 = 1.2 mC; E = ½ × 100 × 10−6 × 12² = 7.2 mJ
Q = charge in coulombs, C = capacitance in farads, V = voltage in volts, E = stored energy in joules
Example: 100 μF at 12 V → Q = 100 × 10−6 × 12 = 1.2 mC; E = ½ × 100 × 10−6 × 12² = 7.2 mJ
Capacitance unit prefixes
| Unit | Farads |
|---|---|
| 1 pF (picofarad) | 10−12 F |
| 1 nF (nanofarad) | 10−9 F |
| 1 μF (microfarad) | 10−6 F |
| 1 mF (millifarad) | 10−3 F |
| 1 F (farad) | 1 F |
Worked examples
- Power-supply filter capacitor: 4,700 μF at 50 V holds 235 mC and stores 5.875 J, enough to give a real shock, which is why such capacitors must be discharged before servicing.
- Decoupling capacitor: 100 nF at 12 V holds just 1.2 μC.
- Supercapacitor: 3,000 F at 2.7 V holds 8,100 C and stores 10,935 J (about 3.04 Wh).
Charge and energy table
| Capacitance | Voltage (V) | Charge (Q) | Stored energy (E) |
|---|---|---|---|
| 10 pF | 5 | 50 pC | 125 pJ |
| 1 nF | 5 | 5 nC | 12.5 nJ |
| 100 nF | 12 | 1.2 μC | 7.2 μJ |
| 10 μF | 5 | 50 μC | 125 μJ |
| 100 μF | 12 | 1.2 mC | 7.2 mJ |
| 1,000 μF | 25 | 25 mC | 312.5 mJ |
| 4,700 μF | 50 | 235 mC | 5.875 J |
| 1 F | 5.5 | 5.5 C | 15.125 J |
| 3,000 F | 2.7 | 8,100 C | 10,935 J |
How fast a capacitor charges
Charging through a resistor follows the time constant τ = R × C (seconds, with R in ohms and C in farads). After one time constant the capacitor reaches about 63.2% of the supply voltage, and after five time constants about 99.3%, which is usually treated as fully charged.
Practical notes
- Respect the voltage rating. Exceeding a capacitor's rated voltage can damage it or cause electrolytic capacitors to fail violently.
- Tolerance matters. Electrolytic capacitors often have tolerances of ±20%, so real charge can differ noticeably from the calculated value.
Related conversions: volts to joules · joules to volts · watts to joules
Q = C × V. 100 μF at 12 V holds 1.2 mC of charge and stores 7.2 mJ of energy.